145-4x=5x^2

Solution for 145-4x=5x^2 equation:

145-4x=5x^2

We move all terms to the left:

145-4x-(5x^2)=0

determiningTheFunctionDomain
-5x^2-4x+145=0

a = -5; b = -4; c = +145;
Δ = b2-4ac
Δ = -42-4·(-5)·145
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-54}{2*-5}=\frac{-50}{-10}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+54}{2*-5}=\frac{58}{-10}
=-5+4/5
$